풀스택/jQuery

jqery 활용 mysite2에 적용시키기 -보충

woohyun22 2019. 2. 14. 19:40
복습겸 순서정리

- 네비게이션에서 연결 action ajax로

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<li><a href="${pageContext.servletContext.contextPath }/guestbook?a=ajax">방명록(Ajax)</a></li>
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- actionfactory


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 else if("ajax".equals(actionName)) {
            action = new AjaxAction();
        }
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- ajaxaction


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public class AjaxAction implements Action {
 
    @Override
    public void execute(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException {
        WebUtils.forward(request, response, "/WEB-INF/views/guestbook/index-ajax.jsp");
    }
 
}
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- index-ajax.jsp로


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<link rel="stylesheet"
    href="${pageContext.request.contextPath }/assets/css/guestbook-ajax.css"
    rel="stylesheet" type="text/css">
<link rel="stylesheet"
    href="https://code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
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- guestbook-ajax.css를 읽어옴


-보충하기

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